Integrand size = 24, antiderivative size = 145 \[ \int \frac {1}{x^3 \sqrt {a^2+2 a b x+b^2 x^2}} \, dx=\frac {-a-b x}{2 a x^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {b (a+b x)}{a^2 x \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {b^2 (a+b x) \log (x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {b^2 (a+b x) \log (a+b x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Time = 0.03 (sec) , antiderivative size = 142, normalized size of antiderivative = 0.98, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {660, 46} \[ \int \frac {1}{x^3 \sqrt {a^2+2 a b x+b^2 x^2}} \, dx=\frac {b (a+b x)}{a^2 x \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {a+b x}{2 a x^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {b^2 \log (x) (a+b x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {b^2 (a+b x) \log (a+b x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Rule 46
Rule 660
Rubi steps \begin{align*} \text {integral}& = \frac {\left (a b+b^2 x\right ) \int \frac {1}{x^3 \left (a b+b^2 x\right )} \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}} \\ & = \frac {\left (a b+b^2 x\right ) \int \left (\frac {1}{a b x^3}-\frac {1}{a^2 x^2}+\frac {b}{a^3 x}-\frac {b^2}{a^3 (a+b x)}\right ) \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}} \\ & = -\frac {a+b x}{2 a x^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {b (a+b x)}{a^2 x \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {b^2 (a+b x) \log (x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {b^2 (a+b x) \log (a+b x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}} \\ \end{align*}
Time = 0.39 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.01 \[ \int \frac {1}{x^3 \sqrt {a^2+2 a b x+b^2 x^2}} \, dx=\frac {\frac {a^3 (a-2 b x)}{\sqrt {a^2} x^2}-\frac {a (a-3 b x) \sqrt {(a+b x)^2}}{x^2}-4 \sqrt {a^2} b^2 \log (x)+2 \left (-a+\sqrt {a^2}\right ) b^2 \log \left (\sqrt {a^2}-b x-\sqrt {(a+b x)^2}\right )+2 \left (a+\sqrt {a^2}\right ) b^2 \log \left (\sqrt {a^2}+b x-\sqrt {(a+b x)^2}\right )}{4 a^4} \]
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Time = 1.96 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.40
method | result | size |
default | \(\frac {\left (b x +a \right ) \left (2 b^{2} \ln \left (x \right ) x^{2}-2 b^{2} \ln \left (b x +a \right ) x^{2}+2 a b x -a^{2}\right )}{2 \sqrt {\left (b x +a \right )^{2}}\, a^{3} x^{2}}\) | \(58\) |
risch | \(\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (\frac {b x}{a^{2}}-\frac {1}{2 a}\right )}{\left (b x +a \right ) x^{2}}+\frac {\sqrt {\left (b x +a \right )^{2}}\, b^{2} \ln \left (-x \right )}{\left (b x +a \right ) a^{3}}-\frac {\sqrt {\left (b x +a \right )^{2}}\, b^{2} \ln \left (b x +a \right )}{\left (b x +a \right ) a^{3}}\) | \(91\) |
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Time = 0.25 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.28 \[ \int \frac {1}{x^3 \sqrt {a^2+2 a b x+b^2 x^2}} \, dx=-\frac {2 \, b^{2} x^{2} \log \left (b x + a\right ) - 2 \, b^{2} x^{2} \log \left (x\right ) - 2 \, a b x + a^{2}}{2 \, a^{3} x^{2}} \]
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\[ \int \frac {1}{x^3 \sqrt {a^2+2 a b x+b^2 x^2}} \, dx=\int \frac {1}{x^{3} \sqrt {\left (a + b x\right )^{2}}}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.66 \[ \int \frac {1}{x^3 \sqrt {a^2+2 a b x+b^2 x^2}} \, dx=-\frac {\left (-1\right )^{2 \, a b x + 2 \, a^{2}} b^{2} \log \left (\frac {2 \, a b x}{{\left | x \right |}} + \frac {2 \, a^{2}}{{\left | x \right |}}\right )}{a^{3}} + \frac {3 \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2}} b}{2 \, a^{3} x} - \frac {\sqrt {b^{2} x^{2} + 2 \, a b x + a^{2}}}{2 \, a^{2} x^{2}} \]
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Time = 0.27 (sec) , antiderivative size = 54, normalized size of antiderivative = 0.37 \[ \int \frac {1}{x^3 \sqrt {a^2+2 a b x+b^2 x^2}} \, dx=-\frac {1}{2} \, {\left (\frac {2 \, b^{2} \log \left ({\left | b x + a \right |}\right )}{a^{3}} - \frac {2 \, b^{2} \log \left ({\left | x \right |}\right )}{a^{3}} - \frac {2 \, a b x - a^{2}}{a^{3} x^{2}}\right )} \mathrm {sgn}\left (b x + a\right ) \]
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Timed out. \[ \int \frac {1}{x^3 \sqrt {a^2+2 a b x+b^2 x^2}} \, dx=\int \frac {1}{x^3\,\sqrt {{\left (a+b\,x\right )}^2}} \,d x \]
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